(X+4)^2=2x^2+7x-14

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Solution for (X+4)^2=2x^2+7x-14 equation: 



(X+4)^2=2X^2+7X-14

We move all terms to the left:

(X+4)^2-(2X^2+7X-14)=0

We get rid of parentheses

-2X^2+(X+4)^2-7X+14=0

We add all the numbers together, and all the variables

-2X^2-7X+(X+4)^2+14=0

We move all terms containing X to the left, all other terms to the right

-2X^2-7X+(X+4)^2=-14

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